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May 06 2018
Question A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. how much time will pipe A alone take to fill the tank?

Here ratio of efficiencies of pipes A, B and C are as follows:

                C             B             A

                2              1

                                2              1

                 4 :           2 :            1

Suppose the efficiencies of pipes C, B and A are 4K, 2K and K

Since, the tank is filled in 5 hours by the three pipes having combined efficiency equal to 7K, the time required to fill the tank by A alone = (7K * 5)/K = 35 hours


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