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February 02 2018
Question A train is running at a speed of 20 meter/sec crosses a pole in 24 sec less that it requires to cross a platform thrice its length at the same speed. What is the length of the train?

Let the length of train = x

Thus the length of the platform = 3x

Thus according to the problem

x/20 = [(x + 3x)/20] – 24

Therefore x = 160 m


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