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July 16 2017
Question A man bought a horse and a cart. If he sold the horse at 10% loss and the cart at 20% gain, he would not lose anything; but if he sold the horse at 5% loss and the cart at 5% gain, he would lose Rs. 10 in the bargain. The amount paid by him for horse and cart is?
Answer

Let x be the cost price of the horse and y be the cost price of the cart. In the first sale there is no losss or profit (i.e.) The loss obtained is equal to the gain.

Therefore (10/100)*x = (20/100)*y

=> x = 2y         ------------(i)

In the second sale, he lost Rs. 10. (i.e.) The loss is greater Than the profit by Rs. 10.

Therefore (5/100)*x = (5/100)*y + 10 -----------------(ii)

Substituting (i) in (ii), we get

(10/100)*y = (5/100)*y + 10

(5/100)*y = 10

y = 200

from (i), 2 * 200 = x = 400.

thus the cost price of Horse = Rs. 400

And Cost Price of cart = Rs. 200

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